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5.6x^2-50x+69=0
a = 5.6; b = -50; c = +69;
Δ = b2-4ac
Δ = -502-4·5.6·69
Δ = 954.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-\sqrt{954.4}}{2*5.6}=\frac{50-\sqrt{954.4}}{11.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+\sqrt{954.4}}{2*5.6}=\frac{50+\sqrt{954.4}}{11.2} $
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